openURL second parameter optional?

[mattekure]

In the new openURL function, the documentation indicates that the second parameter for the callback function is optional. But if I try it without a callback function defined, I get an error of invalid parameter 2.

[Moon Wizard]

Can you try "nil" instead?

JPG

[mattekure]

Can you try "nil" instead?

JPG

Yeah, that works.

So Interface.openURL("https://someurl.com", nil) works

I tried these which did not work
Interface.openURL("https://someurl.com")
Interface.openURL("https://someurl.com", "")

thanks

[Moon Wizard]

I'll look at updating the code to check for the parameter existence first, but you can use nil for now.

Regards,
JPG

[Moon Wizard]

Fixed in beta release today.

Cheers,
JPG

[travin]

Sorry to necro this thread, but when processing the callback, all I get is the URL and not the generated response. Did I miss something or is the generated response stored somewhere else?

[Moon Wizard]

The callback will receive two parameters (sURL, sResponse).

Regards,
JPG

[travin]

The callback will receive two parameters (sURL, sResponse).

Regards,
JPG

Thank you!