Valarian
May 3rd, 2007, 12:55
Is there any way to count the number of successes (over a difficulty number).
For example: roll 4d10 against a difficulty of 6
rolled 4,5,7,2 = 1
rolled 5,6,8,3 = 2
rolled 4,5,3,2 = 0
Ideally, I then want to subtract a success for any ones rolled.
For example: roll 4d10 against a difficulty of 6
rolled 4,5,7,1 = 0
rolled 5,6,8,1 = 1
rolled 4,5,3,1 = -1
No prizes for guessing the ruleset.
For example: roll 4d10 against a difficulty of 6
rolled 4,5,7,2 = 1
rolled 5,6,8,3 = 2
rolled 4,5,3,2 = 0
Ideally, I then want to subtract a success for any ones rolled.
For example: roll 4d10 against a difficulty of 6
rolled 4,5,7,1 = 0
rolled 5,6,8,1 = 1
rolled 4,5,3,1 = -1
No prizes for guessing the ruleset.