Random Encounter....3 foes for every 2 PCs?

[GunbunnyFuFu]

Good day!

Working on trying to generate a random encounter where there are 3 foes for every 2 PCs. Is there a way to do this within Random Encounter? I've tried 2$PC*3, but that ended up with like...64 foes!

Thanks,

GB

[Moon Wizard]

You can try "$PC + ($PC / 2)". It returns an extra 0.5 in the generated encounter field when there is an odd number of characters, but doesn't seem to impact anything.

Regards,
JPG

[GunbunnyFuFu]

Thank you!

[Trenloe]

One thing to note. $PC returns the number of entries in the Party Sheet, not the number of players or active PCs (portraits) on the desktop.

[GunbunnyFuFu]

Thanks for the information..reinforces the need to make sure all of the PCs are on the party sheet!